首先先找到行數跟那行有幾個值的關係而求得行數,再來透過行數找出最後一個值,接著就求出答案了=D
C++(0.016)
/*******************************************************/
/* UVa 913 Joana and the Odd Numbers */
/* Author: Maplewing [at] knightzone.studio */
/* Version: 2011/11/29 */
/*******************************************************/
#include<iostream>
#include<cstdio>
using namespace std;
int main(){
long long N, sum;
while( scanf( "%lld", &N ) != EOF ){
sum = (N+1)/2; // row number;
sum = sum*sum*2-1; // the last number of that row;
sum = 3*sum - 6;
printf( "%lld\n", sum );
}
return 0;
}